This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's how to find the total distance traveled by the car: Step 1: Calculate the distance traveled during the acceleration phase. The car starts from rest (u = 0 m s^-1) and accelerates uniformly to v = 20 m s^-1 in t = 5 s. Using the kinematic equation s = (u+v)/(2)t: s_1 = 0 m s^-1 + 20 m s^-12 × 5 s s_1 = 20 m s^-12 × 5 s s_1 = 10 m s^-1 × 5 s = 50 m Step 2: Calculate the distance traveled during the constant velocity phase. The car travels at a constant velocity of v = 20 m s^-1 for t = 10 s. Using the formula s = v × t: s_2 = 20 m s^-1 × 10 s = 200 m Step 3: Calculate the distance traveled during the braking phase. The car applies brakes, slowing from u = 20 m s^-1 to a stop (v = 0 m s^-1) in t = 6 s. Using the kinematic equation s = (u+v)/(2)t: s_3 = 20 m s^-1 + 0 m s^-12 × 6 s s_3 = 20 m s^-12 × 6 s s_3 = 10 m s^-1 × 6 s = 60 m Step 4: Calculate the total distance traveled. The total distance is the sum of the distances from all three phases. D_total = s_1 + s_2 + s_3 D_total = 50 m + 200 m + 60 m = 310 m The total distance traveled is 310 m. That's 2 down. 3 left today — send the next one.