Calculate the energy consumed by the bulb in one day.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Calculate the energy consumed by the bulb in one day.
The power of the bulb is $P = 200 \text{ W}$.
The time it is lighted for is $t = 1 \text{ day} = 24 \text{ hours}$.
The energy consumed is given by the formula $E = P \times t$.
$$E = 200 \text{ W} \times 24 \text{ h}$$
$$E = 4800 \text{ Wh}$$
Step 2: Convert the energy from Watt-hours (Wh) to kilowatt-hours (kWh).
Since $1 \text{ kWh} = 1000 \text{ Wh}$, we divide the energy in Wh by 1000.
$$E = \frac{4800 \text{ Wh}}{1000 \text{ Wh/kWh}}$$
$$E = 4.8 \text{ kWh}$$
Step 3: Calculate the total cost.
The cost of electricity is N 40 per kWh.
The total cost is the energy consumed (in kWh) multiplied by the rate per kWh.
$$\text{Cost} = E \times \text{Rate}$$
$$\text{Cost} = 4.8 \text{ kWh} \times \text{N } 40/\text{kWh}$$
$$\text{Cost} = \text{N } 192.00$$
The correct option is D.
The final answer is $\boxed{\text{N } 192.00}$.
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