This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the problems. Problem 1 (Circuit with three resistors in series): Step 1: Calculate the total resistance of the series circuit. Given resistors: R_1 = 15 \, , R_2 = 30 \, , R_3 = 45 \, . For resistors connected in series, the total resistance (R_total) is the sum of the individual resistances: R_total = R_1 + R_2 + R_3 R_total = 15 \, + 30 \, + 45 \, R_total = 90 \, Step 2: Calculate the total voltage applied to the circuit using Ohm's Law. Given total current (I) = 1.5 \, A. According to Ohm's Law, the total voltage (V_total) is given by: V_total = I × R_total V_total = (1.5 \, A) × (90 \, ) V_total = 135 \, V The total voltage applied to the circuit is 135 V. Problem 2 (Electrical energy and power rating): a) How much electrical energy is consumed by the bulb in a day? Step 1: Identify the given power and time. Power (P) of the light bulb = 100 \, W. Time (t) of use per day = 8 \, hours. Step 2: Calculate the energy consumed. Energy (E) is calculated as Power × Time. To get the energy in kilowatt-hours (kWh), convert power from Watts to kilowatts. P = 100 \, W = (100)/(1000) \, kW = 0.1 \, kW E = P × t E = (0.1 \, kW) × (8 \, hours) E = 0.8 \, kWh The electrical energy consumed by the bulb in a day is 0.8 kWh. b) An electric heater consumes 2 kWh of electrical energy in 2 hours. What is its power rating? Step 1: Identify the given energy and time. Energy (E) consumed = 2 \, kWh. Time (t) taken = 2 \, hours. Step 2: Calculate the power rating. Power (P) is calculated as Energy divided by Time. P = (E)/(t) P = 2 \, kWh2 \, hours P = 1 \, kW To express in Watts: P = 1 \, kW = 1000 \, W The power rating of the electric heater is 1000 W. 3 done, 2 left today. You're making progress.