Calculate the resistance of the lamp.
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Morning Noh β let's get this done.
Step 1: Calculate the resistance of the lamp.
The voltage ($V$) across the lamp is $6.0 \, \text{V}$ and the current ($I$) through it is $0.53 \, \text{A}$.
Using Ohm's Law, $R = \frac{V}{I}$:
$$R = \frac{6.0 \, \text{V}}{0.53 \, \text{A}}$$
$$R \approx 11.32075 \, \Omega$$
Rounding to three significant figures:
$$R = 11.3 \, \Omega$$
The resistance is $\boxed{\text{11.3 } \Omega}$.
Step 2: Calculate the electrical power transferred in the lamp.
The voltage ($V$) is $6.0 \, \text{V}$ and the current ($I$) is $0.53 \, \text{A}$.
Using the formula for power, $P = VI$:
$$P = (6.0 \, \text{V}) \times (0.53 \, \text{A})$$
$$P = 3.18 \, \text{W}$$
The electrical power transferred is $\boxed{\text{3.18 W}}$.
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