A lamp is connected to a 12 V battery and draws a current of 2.5 A. Calculate the power of the lamp.

Question

ScanSolve AI Tutor · Accepted Answer

Here are the solutions to your problems.

1.

Identify the given values for voltage and current.
We are given the voltage $V = 12 \text{ V}$ and the current $I = 2.5 \text{ A}$ .
Use the formula for electrical power.
The power $P$ of a lamp is calculated using the formula $P = V \times I$ .
Substitute the values and calculate the power.
$P = 12 \text{ V} \times 2.5 \text{ A}$ $P = 30 \text{ W}$
The power of the lamp is $\boxed{\text{30 W}}$ .

2.
Identify the given values for resistance and current.
We are given the resistance $R = 20 \ \Omega$ and the current $I = 4 \text{ A}$ .
Use the formula for power dissipated by a resistor.
The power $P$ dissipated by a heater (resistor) is calculated using the formula $P = I^2 \times R$ .
Substitute the values and calculate the power.
$P = (4 \text{ A})^2 \times 20 \ \Omega$ $P = 16 \text{ A}^2 \times 20 \ \Omega$ $P = 320 \text{ W}$
The power dissipated by the heater is $\boxed{\text{320 W}}$ .

Step-by-step solution