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A light bulb with a resistance of 3Ω is connected to a 12V power source. Calculate the current flowing through the bulb.

Physics

ScanSolve AI Answer

Answer

4A\text{4A}

Step-by-step solution

3 steps
  1. Identify the given values and the formula.

    The voltage (VV) across the bulb is 12V12\text{V}.
    The resistance (RR) of the bulb is 3Ω3\Omega.
    We need to find the current (II).
    Ohm's Law states that V=IRV = IR.

  2. Rearrange Ohm's Law to solve for current.

    I=VRI = \frac{V}{R}
  3. Substitute the given values into the formula and calculate the current.

    I=12V3ΩI = \frac{12\text{V}}{3\Omega} I=4AI = 4\text{A}

    The current through the bulb is 4A\text{4A}.

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