2 The voltage supplied to a circuit is 240 V and the resistance is 60 Ω. Calculate the current flowing in the circuit.

Here are the solutions to the problems using Ohm's Law, V = IR. 3.2 The voltage supplied to a circuit is 240 V and the resistance is 60 \, . Calculate the current flowing in the circuit. Step 1: State the formula for current. Ohm's Law states that V = IR, where V is voltage, I is current, and R is resistance. To find the current, we rearrange the formula to: I = (V)/(R) Step 2: Substitute the given values. Given V = 240 V and R = 60 \, . I = 240\, V60\, Step 3: Calculate the current. I = 4\, A The current flowing in the circuit is 4 A. 3.3 A kettle operates at 12 A when connected to a 240 V supply. Calculate the resistance of the kettle. Step 1: State the formula for resistance. Using Ohm's Law, V = IR, we can rearrange to find resistance: R = (V)/(I) Step 2: Substitute the given values. Given V = 240 V and I = 12 A. R = 240\, V12\, A Step 3: Calculate the resistance. R = 20\, The resistance of the kettle is 20 . QUESTION 4: REASONING AND INTERPRETATION 4.1 A resistor has a constant resistance of 10 \, . 4.1.1 Calculate the current when the voltage is 20 V. Step 1: State the formula for current. I = (V)/(R) Step 2: Substitute the given values. Given V = 20 V and R = 10 \, . I = 20\, V10\, Step 3: Calculate the current. I = 2\, A The current is 2 A. 4.1.2 Calculate the current when the voltage is increased to 40 V. Step 1: State the formula for current. I = (V)/(R) Step 2: Substitute the given values. Given V = 40 V and R = 10 \, . I = 40\, V10\, Step 3: Calculate the current. I = 4\, A The current is 4 A. 4.1.3 What happens to the current when the voltage is doubled? From 4.1.1, when V = 20 V, I = 2 A. From 4.1.2, when V = 40 V (which is double 20 V), I = 4 A (which is double 2 A). When the voltage is doubled, the current also doubles. This is because current is directly proportional to voltage when resistance is constant. That's 2 down. 3 left today — send the next one.