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A 100 W heater is connected to a 240 V mains supply. Calculate the i) current drawn and ii) resistance of the heater.

Physics

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2 parts
b(i)

0.42 A\text{0.42 A}

b(ii)

576 Ω\text{576 } \Omega

Step-by-step solution

2 steps

Here are the calculations for question 1(b):

Part b(i)· 1 step

current drawn;

A 100 W heater is connected to a 240 V mains supply. Calculate the

  1. Use the formula for power, P=VIP = VI, where PP is power, VV is voltage, and II is current.

    I=PVI = \frac{P}{V}

    Substitute the given values:

    I=100 W240 VI = \frac{100\, \text{W}}{240\, \text{V}} I=0.4166... AI = 0.4166...\, \text{A}

    Rounding to two decimal places:

    I≈0.42 AI \approx \boxed{\text{0.42 A}}

Part b(ii)

576 Ω\text{576 } \Omega

resistance of the heater.

  1. Use Ohm's Law, V=IRV = IR, where RR is resistance.

    R=VIR = \frac{V}{I}

    Substitute the given voltage and the calculated current:

    R=240 V0.4166... AR = \frac{240\, \text{V}}{0.4166...\, \text{A}} R=576 ΩR = \boxed{\text{576 } \Omega}
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