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A heating element has a power rating of 1850 W and is connected to a 220 V supply. Calculate the energy dissipated in 3 minutes, the current through the element, and its resistance.

Physics

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Answers

3 parts
a

333000 J\text{333000 J}

b

8.41 A\text{8.41 A}

c

26.16 Ω\text{26.16 } \Omega

Step-by-step solution

6 steps
  1. The relationship between energy (EE), power (PP), and time (tt) is:

    E=P×tE = P \times t

    This means energy is the product of power and the time for which the power is used.

  2. Given: Voltage V=220 VV = 220\, \text{V} Power P=1850 WP = 1850\, \text{W}

Part a· 2 steps

The energy dissipated by the element in 3 min3\, \text{min}.

  1. Convert time to seconds.

    $$
    t = 3\, \text{min} \times \frac{60\, \text{s}}{1\, \text{min}} = 180\, \text{s}
    $$
    
  2. Calculate the energy dissipated using the formula E=P×tE = P \times t.

    $$
    E = 1850\, \text{W} \times 180\, \text{s}
    $$
    $$
    E = 333000\, \text{J}
    $$
    The energy dissipated is $\boxed{\text{333000 J}}$.
    

Part b

8.41 A\text{8.41 A}

The current through the element.

  1. Use the formula for power P=V×IP = V \times I, where II is the current.

    Rearrange to solve for II. I=PV I = \frac{P}{V}

  2. Substitute the given values and calculate the current.

    $$
    I = \frac{1850\, \text{W}}{220\, \text{V}}
    $$
    $$
    I \approx 8.409\, \text{A}
    $$
    The current through the element is approximately $\boxed{\text{8.41 A}}$.
    

Part c

26.16 Ω\text{26.16 } \Omega

The resistance of the element.

  1. Use the formula for power P=V2RP = \frac{V^2}{R}, where RR is the resistance.

    Rearrange to solve for RR. R=V2P R = \frac{V^2}{P}

  2. Substitute the given values and calculate the resistance.

    $$
    R = \frac{(220\, \text{V})^2}{1850\, \text{W}}
    $$
    $$
    R = \frac{48400\, \text{V}^2}{1850\, \text{W}}
    $$
    $$
    R \approx 26.162\, \Omega
    $$
    The resistance of the element is approximately $\boxed{\text{26.16 } \Omega}$.
    
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