Calculate the total equivalent resistance of the circuit.

The two $60 \, \Omega$ resistors are connected in parallel. Calculate their equivalent resistance, $R_p$.

$$R_p = \frac{R_1 \times R_2}{R_1 + R_2}$$ $$R_p = \frac{60 \, \Omega \times 60 \, \Omega}{60 \, \Omega + 60 \, \Omega}$$ $$R_p = \frac{3600 \, \Omega^2}{120 \, \Omega}$$ $$R_p = 30 \, \Omega$$

The $180 \, \Omega$ resistor is in series with the equivalent resistance $R_p$. Let's call this combination $R_s$.

$$R_s = 180 \, \Omega + R_p$$ $$R_s = 180 \, \Omega + 30 \, \Omega$$ $$R_s = 210 \, \Omega$$

The $25 \, \Omega$ resistor is in series with $R_s$.

$$R_T = 25 \, \Omega + R_s$$ $$R_T = 25 \, \Omega + 210 \, \Omega$$ $$R_T = 235 \, \Omega$$

The total equivalent resistance is $\text{235 } \Omega$.