🔹 Question 4 Three resistors 2 Ω, 3 Ω, and 5 Ω are connected in series across a 20 V battery. Find the total current flowing through the circuit. 🔹 Question 5 In the same circuit as Question 4, find the voltage drop across the 3 Ω resistor. 🔹 Question 6 Two resistors, R1=8 Ω and R2=4 Ω, are connected in parallel, and the combination is connected in series with a 2 Ωresistor. The circuit is connected to a 24 V battery. Calculate: a) The total resistance b) The total current c) The power dissipated in the 4 Ωresistor 🔹 Question 7 Three resistors are connected in parallel. Two of them have values 3 Ω and 6 Ω. The total resistance is 1.5 Ω. Calculate the value of the third resistor.

Step 1: Calculate the total resistance of the series circuit. For resistors connected in series, the total resistance R_total is the sum of individual resistances. R_total = R_1 + R_2 + R_3 R_total = 2 \, + 3 \, + 5 \, R_total = 10 \, Step 2: Use Ohm's Law to find the total current flowing through the circuit. Ohm's Law states V = I R, where V is the total voltage, I is the total current, and R is the total resistance. I_total = V_totalR_total I_total = 20 \, V10 \, I_total = 2 \, A The total current flowing through the circuit is 2 A. That's 2 down. 3 left today — send the next one.