Problem solving/show you solution 2. A series circuit has a 9V battery connected to two resistors, R1 = 3Ω and R2= 6Ω. What is the current flowing through the circuit? 3.In a series circuit, the current is 2A, and the total voltage supplied is 12V. If R1 = 4Ω, what is the
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2. A series circuit has a 9V battery connected to two resistors, R1 = 3Ω and R2= 6Ω. What is the current flowing through the circuit?
The current flowing through the circuit is 1A.
Steps:
Calculate the total resistance (R_total) in the series circuit
In a series circuit, the total resistance is the sum of individual resistances.
R_total = R1 + R2
R_total = 3Ω + 6Ω
R_total = 9ΩApply Ohm's Law to find the current (I)
Ohm's Law states V = I * R_total, so I = V / R_total.
I = 9V / 9Ω
I = 1A
Part 2
3. In a series circuit, the current is 2A, and the total voltage supplied is 12V. If R1 = 4Ω, what is the
This question is incomplete. However, based on the provided information, we can calculate the total resistance of the circuit.
Steps to calculate total resistance:
- Apply Ohm's Law to find the total resistance (R_total): Ohm's Law states V_total = I * R_total, so R_total = V_total / I. R_total = 12V / 2A R_total = 6Ω
If the question intended to ask for the value of a second resistor (R2), it would be:
R_total = R1 + R2
6Ω = 4Ω + R2
R2 = 6Ω - 4Ω
R2 = 2Ω
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