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A circuit has a 3 Ohm and a 6 Ohm resistor in series with a parallel combination of a 4.5 Ohm and a 1.5 Ohm resistor. An ammeter reads 5.25 A. Calculate the total external resistance, the reading on v
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4 stepsHere's the solution to your circuit problem:
7.1 State Ohm's law in words.
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points, provided the temperature and other physical conditions remain constant.
7.2 The reading on the ammeter is 5.25 A.
7.2.1 Calculate the total external resistance of the circuit.
Calculate the equivalent resistance of the parallel combination of 4.5 Ω and 1.5 Ω (R_p).
R_p = (R₁ × R₂)/(R₁ + R₂)
R_p = (4.5 Ω × 1.5 Ω)/(4.5 Ω + 1.5 Ω)
R_p = (6.75 Ω²)/(6.0 Ω)
R_p = 1.125 ΩCalculate the total external resistance (R_ext) by adding the series resistors.
R_ext = R_p + 3 Ω + 6 Ω
R_ext = 1.125 Ω + 3 Ω + 6 Ω
R_ext = 10.125 Ω7.2.2 Calculate the reading on voltmeter V₁.
Use Ohm's Law for the external circuit.
V₁ = I × R_ext
Given I = 5.25 A (ammeter reading)
R_ext = 10.125 Ω (from 7.2.1)Substitute values and calculate V₁.
V₁ = 5.25 A × 10.125 Ω
V₁ = 53.15625 V7.2.3 How does the reading on voltmeter V₂ compare to the reading on voltmeter V₁? Choose from SMALLER THAN, EQUAL TO or GRE
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