Here why are conversions like that

Physics

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Answer

Conversions are structured the way they are to change a measurement from one unit to another without changing its actual value. This is done using conversion factors.

Step-by-step solution

2 steps
  1. Understand the concept of a conversion factor.

    A conversion factor is a ratio of two equivalent quantities expressed in different units. Since the numerator and denominator represent the same amount, the conversion factor is essentially equal to 1.
    For example, we know that 1 m1 \text{ m} is the same length as 1000 mm1000 \text{ mm}.
    So, we can form two conversion factors:

    1000 mm1 mor1 m1000 mm\frac{1000 \text{ mm}}{1 \text{ m}} \quad \text{or} \quad \frac{1 \text{ m}}{1000 \text{ mm}}

    Both of these fractions are equal to 1.

  2. Apply the conversion factor.

    To convert a quantity, you multiply it by the appropriate conversion factor. The goal is to choose the factor that allows the original unit to cancel out, leaving the desired unit.

    Let's use the example of converting 5 m5 \text{ m} to millimeters:

    5 m×1000 mm1 m5 \text{ m} \times \frac{1000 \text{ mm}}{1 \text{ m}}

    Here, the unit 'm' in the numerator of 5 m5 \text{ m} cancels with the unit 'm' in the denominator of the conversion factor:

    5 m×1000 mm1 m=5×1000 mm=5000 mm5 \cancel{\text{ m}} \times \frac{1000 \text{ mm}}{1 \cancel{\text{ m}}} = 5 \times 1000 \text{ mm} = 5000 \text{ mm}

    If we had chosen the other conversion factor, the units would not cancel correctly:

    5 m×1 m1000 mm=5 m21000 mm5 \text{ m} \times \frac{1 \text{ m}}{1000 \text{ mm}} = \frac{5 \text{ m}^2}{1000 \text{ mm}}

    This result is not in millimeters, indicating the wrong conversion factor was used.

    The structure of conversions ensures that you are multiplying by 1 (so the value doesn't change) while simultaneously changing the units by cancelling them out.

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