I asked for U to help me find the work in the picture

Physics

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Answer

216.5 J216.5 \, \text{J}

Step-by-step solution

4 steps

To find the work done, we use the formula for work done by a constant force.

  1. Identify the given values from the picture.

    • Force, F=100 NF = 100 \, \text{N}
    • Displacement, d=5 md = 5 \, \text{m}
    • Angle between the force and displacement, θ=30∘\theta = 30^\circ
  2. State the formula for work done (WW).

    W=F⋅d⋅cos⁡(θ)W = F \cdot d \cdot \cos(\theta)
  3. Substitute the given values into the formula.

    W=100 N⋅5 m⋅cos⁡(30∘)W = 100 \, \text{N} \cdot 5 \, \text{m} \cdot \cos(30^\circ)
  4. Calculate the value of cos⁡(30∘)\cos(30^\circ) and then the work done.

    cos⁡(30∘)=32≈0.866\cos(30^\circ) = \frac{\sqrt{3}}{2} \approx 0.866 W=100 N⋅5 m⋅32W = 100 \, \text{N} \cdot 5 \, \text{m} \cdot \frac{\sqrt{3}}{2} W=500⋅32 JW = 500 \cdot \frac{\sqrt{3}}{2} \, \text{J} W=2503 JW = 250 \sqrt{3} \, \text{J} W≈250×0.866 JW \approx 250 \times 0.866 \, \text{J} W≈216.5 JW \approx 216.5 \, \text{J}

    The work done is:

    216.5 J216.5 \, \text{J}
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