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Identify and resolve the contradiction in the circuit diagram regarding the 3 resistor's current and voltage.

Physics

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QUESTION 4

The circuit diagram contains contradictory information, specifically regarding the current through the 3Ω3 \Omega resistor (labeled as 6 A6 \text{ A}) and the voltage across it (labeled as V1=5 VV_1 = 5 \text{ V}). If 6 A6 \text{ A} flows through a 3Ω3 \Omega resistor, the voltage across it should be 18 V18 \text{ V}. If the voltage across it is 5 V5 \text{ V}, the current should be 5 V/3Ω≈1.67 A5 \text{ V} / 3 \Omega \approx 1.67 \text{ A}.

To proceed, I will make the following assumptions, which allow for a consistent solution based on standard circuit laws:

  • The total current from the battery is $
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