A box of mass 40 kg is being dragged along the floor by a rope inclined at 60° to the horizontal. The frictional force between the box and the floor is 100N and the tension on the rope is 300N. How much work is done in dragging the box through a distance of 4m?

March 20, 2026Physics

ScanSolve AI Answer

March 20, 2026

Answer

400 J

Step 1: Identify the work done in dragging the box.
The work done in dragging the box against friction is given by the formula
$W = f \cdot d,$
where $f$ is the frictional force and $d$ is the displacement along the floor.

Step 2: Substitute the given values.
$f = 100~\mathrm{N}$ , $d = 4~\mathrm{m}$ .
$W = 100~N \times 4~\mathrm{m}$

Step 3: Simplify.
$W = 400~\mathrm{J}$

B. 400 J
400 J

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Identify the work done in dragging the box. The work done in dragging the box against friction is given by the formula W = f · d, where f is the frictional force and d is the displacement along the floor.

Asked on March 20, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 20, 2026

Step 1: Identify the work done in dragging the box. The work done in dragging the box against friction is given by the formula W = f · d, where f is the frictional force and d is the displacement along the floor. Step 2: Substitute the given values. f = 100~N, d = 4~m. W = 100~N × 4~m Step 3: Simplify. W = 400~J B. 400 J 400 J