In the diagram above, a ball placed on top of a tower 150 m high is kicked with a velocity of 20 m s−1 to hit the ground at a distance, S, as shown. Determine the value of S. [Take g = 10.0 m s−2]

The initial vertical velocity is $u_y = 0$ m/s since the ball is kicked horizontally. The vertical displacement is $h = 150$ m, and the acceleration due to gravity is $g = 10.0$ m/s$^2$.
Using the equation of motion $h = u_y t + \frac{1}{2}gt^2$:

The horizontal velocity is constant, $u_x = 20$ m/s. The horizontal distance $S$ is given by $S = u_x t$.

Rounding to a reasonable number of significant figures (e.g., three, based on input values):

The value of $S$ is $\boxed{\text{110 m}}$

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