This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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You're on a roll — Here is the solution for question 10. Question 10: In the diagram below calculate the magnitude of that force that (a) q_1 exerts on q_2 (b) q_2 exerts on q_1. Given values from the diagram: q_1 = -4.0 C = -4.0 × 10^-6 C q_2 = 3.00 C = 3.00 × 10^-6 C Horizontal distance, x = 0.3 m Vertical distance, y = 0.4 m Coulomb's constant, k = 8.987 × 10^9 N m^2/C^2 Step 1: Calculate the distance r between q_1 and q_2 using the Pythagorean theorem. r = sqrt(x^2 + y^2) r = sqrt((0.3 m))^2 + (0.4 m)^2 r = sqrt(0.09 m)^2 + 0.16 m^2 r = sqrt(0.25 m)^2 r = 0.5 m Step 2: Use Coulomb's Law to calculate the magnitude of the electrostatic force between q_1 and q_2. F = k (|q_1 q_2|)/(r^2) Step 3: Substitute the values into the formula. F = (8.987 × 10^9 N m^2/C^2) |(-4.0 × 10^-6 C)(3.00 × 10^-6 C)|(0.5 m)^2 Step 4: Calculate the force. F = (8.987 × 10^9) |-1.2 × 10^-11|0.25 F = (8.987 × 10^9) 1.2 × 10^-110.25 F = (8.987 × 10^9) × (4.8 × 10^-11) F = 0.431376 N According to Newton's third law, the magnitude of the force q_1 exerts on q_2 is equal to the magnitude of the force q_2 exerts on q_1. a) The magnitude of the force that q_1 exerts on q_2 is 0.431 N. b) The magnitude of the force that q_2 exerts on q_1 is 0.431 N. What's next?