This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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You're on a roll — here are the answers to the remaining questions: 2.3.2 Calculate the output force, if the input force is 50N, the input piston's area is 100mm² and the output piston's area is 800mm². This was calculated in the previous response as part of 2.3.1. The output force is 400 N. 2.3.3 Draw a systems diagram for the above hydraulic system. INSET: Draw a small piston with an arrow indicating an input force (effort) being applied downwards. PROCESS: Draw a container filled with fluid, connected by a pipe to both pistons. Indicate that pressure is transmitted through the fluid. OUTPUT: Draw a larger piston with an arrow indicating an upward output force (load) being exerted. 2.4 In the hydraulic press below; a force of 100 N is applied to piston A and it moves down 10 cm. 2.4.1 Calculate the work done by both pistons. Step 1: Calculate the work done by piston A (input work). Work done (W) is calculated as force (F) multiplied by distance (d). W_A = F_A × d_A Given: F_A = 100 \, N d_A = 10 \, cm = 0.1 \, m Substitute the values: W_A = 100 \, N × 0.1 \, m W_A = 10 \, J Step 2: Calculate the work done by piston B (output work). In an ideal hydraulic system, the work input equals the work output due to the conservation of energy. W_B = W_A W_B = 10 \, J The work done by both pistons is 10 J. 2.4.2 Calculate the pressure of the fluid. Step 1: Convert the area of piston A to square meters. A_A = 10 \, cm^2 1 \, cm = 0.01 \, m 1 \, cm^2 = (0.01 \, m)^2 = 0.0001 \, m^2 = 10^-4 \, m^2 A_A = 10 × 10^-4 \, m^2 = 10^-3 \, m^2 Step 2: Calculate the pressure (P) using the force and area of piston A. P = (F_A)/(A_A) Given: F_A = 100 \, N A_A = 10^-3 \, m^2 Substitute the values: P = 100 \, N10^-3 \, m^2 P = 100 × 10^3 \, Pa P = 100000 \, Pa The pressure of the fluid is 100000 Pa or 100 kPa. Got more? Send 'em!