Calculate the inductance and capacitance per phase for an overhead line given its length, conductor diameter, and assuming free space.

April 15, 2026Physics

ScanSolve AI Answer

April 15, 2026

Answer

18 km = 18 \times 10^3 \text{ m}$

Here's how to calculate the inductance and capacitance per phase for the given overhead line:

Given: Line length $L_{line} = 18 km = 18 \times 10^3 \text{ m}$ Conductor diameter $d = 1 cm = 0.01 \text{ m}$ Conductor radius $r = d/2 = 0.005 \text{ m}$

Constants: Permeability of free space $\mu_0 = 4\pi \times 10^{-7} \text{ H/m}$ Permittivity of free space $\epsilon_0 = 8.854 \times 10^{-12} \text{ F/m}$

Formulas: Inductance per phase per meter: $L_{per\_meter} = \frac{\mu_0}{2\pi} \ln\left(\frac{D_{eq}}{r'}\right)$ Cap

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

More Physics Questions

QA force of 20 N is applied to a material with a cross-sectional area of 5 cm2. Calculate the stress.QList and explain four topics covered in Chapter 1 of the textbook.QWhy cloud index model is suitable for optimize the amount of insolation using satellite data QMore than 20 word problems In kinetic energy QWhy optical weight is attached to angstrom model for optimization

See all Physics questions →

Still have questions?

Quick Answer

Here's how to calculate the inductance and capacitance per phase for the given overhead line: Given: Line length L_line = 18 km = 18 × 10^3 m Conductor diameter d = 1 cm = 0.01 m Conductor radius r = d/2 = 0.005 m Constants: Permeability of free space…

Asked on April 15, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on April 15, 2026

Here's how to calculate the inductance and capacitance per phase for the given overhead line: Given: Line length L_line = 18 km = 18 × 10^3 m Conductor diameter d = 1 cm = 0.01 m Conductor radius r = d/2 = 0.005 m Constants: Permeability of free space _0 = 4 × 10^-7 H/m Permittivity of free space _0 = 8.854 × 10^-12 F/m Formulas: Inductance per phase per meter: L_per\_meter = (_0)/(2) (D_eqr') Cap