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The mass of an elevator is 500 kg. Calculate the tension in the cable when the elevator is (i) stationary, (ii) ascending with acceleration 2 m/s², (iii) descending with acceleration 2 m/s². Take g = 9.8 m/s².

Physics

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3 parts
i

4900 N\text{4900 N}

ii

5900 N\text{5900 N}

iii

3900 N\text{3900 N}

Step-by-step solution

6 steps

Here are the calculations for the tension in the elevator cable under the given conditions.

Given:
Mass of elevator, m=500 Kgm = 500 \text{ Kg}
Acceleration due to gravity, g=9.8 m/s2g = 9.8 \text{ m/s}^2
Acceleration of elevator, a=2 m/s2a = 2 \text{ m/s}^2

The forces acting on the elevator are the tension TT (upwards) and its weight mgmg (downwards).
According to Newton's second law, the net force ∑F=ma\sum F = ma.
Taking the upward direction as positive:

∑F=T−mg\sum F = T - mg

So, T−mg=maT - mg = ma.
Rearranging for tension:

T=mg+maT = mg + ma

Part i· 2 steps

Stationary

When the elevator is stationary, its acceleration a=0 m/s2a = 0 \text{ m/s}^2.

  1. Substitute the values into the tension formula.

    T=mg+m(0)T = mg + m(0) T=mgT = mg
  2. Calculate the tension.

    T=(500 Kg)(9.8 m/s2)T = (500 \text{ Kg})(9.8 \text{ m/s}^2) T=4900 NT = 4900 \text{ N}

    The tension in the cable when the elevator is stationary is 4900 N\boxed{\text{4900 N}}.

Part ii

5900 N\text{5900 N}

Ascending with an acceleration of 2 m/s22 \text{ m/s}^2

When the elevator is ascending, the acceleration a=+2 m/s2a = +2 \text{ m/s}^2 (positive because it's upwards).

  1. Substitute the values into the tension formula.

    T=mg+maT = mg + ma T=m(g+a)T = m(g+a)
  2. Calculate the tension.

    T=500 Kg(9.8 m/s2+2 m/s2)T = 500 \text{ Kg} (9.8 \text{ m/s}^2 + 2 \text{ m/s}^2) T=500 Kg(11.8 m/s2)T = 500 \text{ Kg} (11.8 \text{ m/s}^2) T=5900 NT = 5900 \text{ N}

    The tension in the cable when the elevator is ascending is 5900 N\boxed{\text{5900 N}}.

Part iii

3900 N\text{3900 N}

Descending with the same acceleration (2 m/s22 \text{ m/s}^2)

When the elevator is descending, the acceleration a=−2 m/s2a = -2 \text{ m/s}^2 (negative because it's downwards).

  1. Substitute the values into the tension formula.

    T=mg+maT = mg + ma T=m(g+a)T = m(g+a)
  2. Calculate the tension.

    T=500 Kg(9.8 m/s2+(−2 m/s2))T = 500 \text{ Kg} (9.8 \text{ m/s}^2 + (-2 \text{ m/s}^2)) T=500 Kg(9.8 m/s2−2 m/s2)T = 500 \text{ Kg} (9.8 \text{ m/s}^2 - 2 \text{ m/s}^2) T=500 Kg(7.8 m/s2)T = 500 \text{ Kg} (7.8 \text{ m/s}^2) T=3900 NT = 3900 \text{ N}

    The tension in the cable when the elevator is descending is 3900 N\boxed{\text{3900 N}}.

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