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Match the following terms with their definitions and answer the questions about pressure, force, and barometers.

Physics

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C. Match the following:

  1. Pressure →\rightarrow a. Pascal
  2. Barometer →\rightarrow f. Atmospheric pressure
  3. Weight →\rightarrow d. Gravitational force
  4. Torricelli barometer →\rightarrow e. Simple barometer
  5. Increased pressure →\rightarrow c. Decreased contact area
  6. S.I. Unit →\rightarrow b. P (Assuming 'P' refers to the common symbol for pressure, as 'Pascal' is already matched with the SI unit of pressure.)

D. Answer the following questions:

1. What is the SI unit of pressure?
The SI unit of pressure is the Pascal (Pa).

2. On which things pressure depends?
Pressure depends on two main factors:

  • The force applied.
  • The area over which the force is distributed.

3. How would you distinguish between force and pressure?
Force is a push or pull that can cause an object to accelerate or deform; it is a vector quantity. Pressure is the force applied perpendicular to a surface per unit area; it is a scalar quantity.

4. How does the pressure exerted by liquid change with depth?
The pressure exerted by a liquid increases with depth because the weight of the liquid column above a point increases.

5. A drawing pin is pushed against a wooden table with a force of 10 N. Calculate the pressure exerted by the pin at a point on a table if the area of the point is 180 cm2^2.

Step 1: Identify the given values.

F=10 NF = 10 \text{ N} A=180 cm2A = 180 \text{ cm}^2

Step 2: Convert the area to square meters (m2^2).

A=180 cm2×(1 m100 cm)2A = 180 \text{ cm}^2 \times \left(\frac{1 \text{ m}}{100 \text{ cm}}\right)^2 A=180×110000 m2A = 180 \times \frac{1}{10000} \text{ m}^2 A=0.018 m2A = 0.018 \text{ m}^2

Step 3: Calculate the pressure using the formula P=FAP = \frac{F}{A}.

P=10 N0.018 m2P = \frac{10 \text{ N}}{0.018 \text{ m}^2} P≈555.56 PaP \approx 555.56 \text{ Pa}

The pressure exerted by the pin is 555.56 Pa\boxed{\text{555.56 Pa}}.

6. A person weight of 120, 96. The area under one foot of the person is 180 cm2^2. Find the pressure exerted on the ground by the person. When he is standing?
Assumption: The person's weight is 120 N, and they are standing on two feet. The area under one foot is 180 cm2^2.

Step 1: Identify the given values.

Ftotal=120 NF_{\text{total}} = 120 \text{ N} Aone foot=180 cm2A_{\text{one foot}} = 180 \text{ cm}^2

Step 2: Calculate the total area of contact when standing on two feet.

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