Maximum hight Range covered Time taken In a projection and land on same plane

Here are the formulas for projectile motion when the projection and landing are on the same horizontal plane: Let: u = initial velocity; θ = angle of projection with the horizontal; g = acceleration due to gravity 1. Maximum height (H): H = (u² sin²θ) / (2g) 2. Range covered (R): R = (u² sin(2θ)) / g 3. Time taken (T) / Time of flight: T = (2u sinθ) / g

Maximum hight Range covered Time taken In a projection and land on same plane

Here are the formulas for projectile motion when the projection and landing are on the same horizontal plane: Let: u = initial velocity; θ = angle of projection with the horizontal; g = acceleration due to gravity 1. Maximum height (H): H = (u² sin²θ) / (2g) 2. Range covered (R): R = (u² sin(2θ)) / g 3. Time taken (T) / Time of flight: T = (2u sinθ) / g

Solved: Maximum hight Range covered Time taken In a…

Here are the formulas for projectile motion when the projection and landing are on the same horizontal plane:

Let:

u = initial velocity
θ = angle of projection with the horizontal
g = acceleration due to gravity

Maximum height (H): H = (u² sin²θ) / (2g)
Range covered (R): R = (u² sin(2θ)) / g
Time taken (T) / Time of flight: T = (2u sinθ) / g

Maximum hight Range covered Time taken In a projection and land on same plane

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