This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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17. (i) Give an example of a machine where the load is between the fulcrum and the effort. (ii) A wheel and axle is used to raise a man whose weight is 800N by the application of 250N. The radii of the wheel and axle are 800mm and 200mm respectively, what is the efficiency of the machine? i) Example of a machine where the load is between the fulcrum and the effort. This describes a Class 2 lever. Example: A wheelbarrow. ii) Efficiency of a wheel and axle. Given: Load F_L = 800 N Effort F_E = 250 N Wheel radius R_W = 800 mm = 0.8 m Axle radius R_A = 200 mm = 0.2 m Step 1: Calculate the Mechanical Advantage (MA). MA = LoadEffort = (F_L)/(F_E) MA = 800 N250 N = 3.2 Step 2: Calculate the Velocity Ratio (VR). VR = Radius of WheelRadius of Axle = (R_W)/(R_A) VR = 0.8 m0.2 m = 4 Step 3: Calculate the efficiency (). = (MA)/(VR) × 100\% = (3.2)/(4) × 100\% = 0.8 × 100\% = 80\% The efficiency of the machine is 80\%.