A student was using a machine of velocity ratio of 1 where he applied an effort of 750N and had a load of 2000N. Calculate the efficiency of the machine and give a conclusion depending on the final answer for efficiency?

Faida ya Kimakanika (MA) inakokotolewa kama uwiano wa mzigo (load) kwa juhudi (effort).
$$
\text{MA} = \frac{\text{Mzigo}}{\text{Juhudi}}
$$
$$
\text{MA} = \frac{2000\, \text{N}}{750\, \text{N}}
$$
$$
\text{MA} = \frac{8}{3} \approx 2.67
$$

Ufanisi unakokotolewa kama uwiano wa Faida ya Kimakanika (MA) kwa Uwiano wa Kasi (Velocity Ratio, VR), kisha kuzidisha kwa 100% ili kupata asilimia.
$$
\text{Ufanisi} = \frac{\text{MA}}{\text{VR}} \times 100\%
$$
Tunapewa $\text{VR} = 3$.
$$
\text{Ufanisi} = \frac{8/3}{3} \times 100\%
$$
$$
\text{Ufanisi} = \frac{8}{9} \times 100\%
$$
$$
\text{Ufanisi} \approx 0.8889 \times 100\%
$$
$$
\text{Ufanisi} \approx \boxed{\text{88.89\%}}
$$

Kwa kuwa ufanisi ni chini ya 100%, hii inaonyesha kuwa mashine si bora (ideal) na sehemu ya nishati inapotea, hasa kutokana na msuguano.