We read your photo as:

Calculate the efficiency of a machine if 6000 J of work is needed to lift a mass of 110 kg through a vertical height of 4 m

June 28, 2026Physics

ScanSolve AI Answer

Answer

\text{73.33\%}

3 steps

Huu hapa ni ufumbuzi wa tatizo hilo:

Tambua data iliyotolewa.
Kazi iliyowekwa ( $W_{input}$ ) ni $6000 \, \text{J}$ .
Masi ( $m$ ) inayoinuliwa ni $110 \, \text{kg}$ .
Urefu ( $h$ ) wa wima ni $4 \, \text{m}$ .
Tunatumia thamani ya kuongeza kasi ya mvutano ( $g$ ) kama $10 \, \text{m/s}^2$ .
Kokotoa kazi iliyofanywa (work output).
Kazi iliyofanywa ni kazi inayohitajika kuinua mzigo, ambayo ni sawa na nishati uwezo inayopatikana.
$W_{output} = mgh$ $W_{output} = 110 \, \text{kg} \times 10 \, \text{m/s}^2 \times 4 \, \text{m}$ $W_{output} = 4400 \, \text{J}$
Kokotoa ufanisi (efficiency).
Ufanisi wa mashine huhesabiwa kwa kutumia formula:
$\text{Ufanisi} = \frac{\text{Work output}}{\text{Work input}} \times 100\%$ $\text{Ufanisi} = \frac{4400 \, \text{J}}{6000 \, \text{J}} \times 100\%$ $\text{Ufanisi} = 0.7333 \times 100\%$ \text{Ufanisi} = \boxed{\text{73.33%}}