We read your photo as:

Calculate the work done when lifting objects of different masses and heights.

Physics

ScanSolve AI Answer

Step-by-step solution

14 steps

Here are the calculations for the work done in each question. The formula for work done is W=F×dW = F \times d, where FF is the force and dd is the distance. For lifting objects, the force required is equal to the object's weight, F=mgF = mg, where mm is the mass and gg is the acceleration due to gravity (9.8 m/s29.8 \text{ m/s}^2).

1. A 500g book is lifted 210cm high. Calculate the work done.

  1. Convert units.

    m=500 g=0.5 kgm = 500 \text{ g} = 0.5 \text{ kg} d=210 cm=2.1 md = 210 \text{ cm} = 2.1 \text{ m}
  2. Calculate the force (weight).

    F=m×g=0.5 kg×9.8 m/s2=4.9 NF = m \times g = 0.5 \text{ kg} \times 9.8 \text{ m/s}^2 = 4.9 \text{ N}
  3. Calculate the work done.

    W=F×d=4.9 N×2.1 m=10.29 JW = F \times d = 4.9 \text{ N} \times 2.1 \text{ m} = 10.29 \text{ J}

    The work done is 10.29 J\boxed{\textbf{10.29 J}}.

    2. A 2kg ball is lifted 50cm from the floor. Calculate the work done.

  4. Convert units.

    d=50 cm=0.5 md = 50 \text{ cm} = 0.5 \text{ m}
  5. Calculate the force (weight).

    F=m×g=2 kg×9.8 m/s2=19.6 NF = m \times g = 2 \text{ kg} \times 9.8 \text{ m/s}^2 = 19.6 \text{ N}
  6. Calculate the work done.

    W=F×d=19.6 N×0.5 m=9.8 JW = F \times d = 19.6 \text{ N} \times 0.5 \text{ m} = 9.8 \text{ J}

    The work done is 9.8 J\boxed{\textbf{9.8 J}}.

    3. A 1500g load is lifted 2m high. Calculate the work done.

  7. Convert units.

    m=1500 g=1.5 kgm = 1500 \text{ g} = 1.5 \text{ kg}
  8. Calculate the force (weight).

    F=m×g=1.5 kg×9.8 m/s2=14.7 NF = m \times g = 1.5 \text{ kg} \times 9.8 \text{ m/s}^2 = 14.7 \text{ N}
  9. Calculate the work done.

    W=F×d=14.7 N×2 m=29.4 JW = F \times d = 14.7 \text{ N} \times 2 \text{ m} = 29.4 \text{ J}

    The work done is 29.4 J\boxed{\textbf{29.4 J}}.

    4. A 3kg box is pushed 250cm across the floor. Calculate the work done.
    Note: For horizontal motion, work done depends on the applied force and friction. Since no friction or applied force is given, and given the context of other problems involving lifting, we will assume the question implies the work done if the force applied is equal to the object's weight, or if it were lifted by that distance for simplification.

  10. Convert units.

    d=250 cm=2.5 md = 250 \text{ cm} = 2.5 \text{ m}
  11. Calculate the force (weight).

    F=m×g=3 kg×9.8 m/s2=29.4 NF = m \times g = 3 \text{ kg} \times 9.8 \text{ m/s}^2 = 29.4 \text{ N}
  12. Calculate the work done.

    W=F×d=29.4 N×2.5 m=73.5 JW = F \times d = 29.4 \text{ N} \times 2.5 \text{ m} = 73.5 \text{ J}

    The work done is 73.5 J\boxed{\textbf{73.5 J}}.

    5. A 750g object is lifted 1.5m high. Calculate the work done.

  13. Convert units.

    m=750 g=0.75 kgm = 750 \text{ g} = 0.75 \text{ kg}
  14. Calculate the force (weight).

    F=m×g=0.75 kg×9.8 m/s2=7.35 NF = m \times g = 0.75 \text{ kg} \times 9.8 \text{ m/s}^2 = 7.35 \text{ N}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp