Calculate the work done against gravity and the work done by an applied force when moving a trolley up a slope.

Mass of trolley, $m = 30 \text{ kg}$
Vertical height gained, $h = 10 \text{ m}$
Acceleration due to gravity, $g = 10 \text{ m/s}^2$ (assuming this standard approximation)

The work done against the gravitational force is $\boxed{\text{3000 J}}$.

Applied force, $F = 100 \text{ N}$ (parallel to the slope)
Vertical height, $h = 10 \text{ m}$
Angle of inclination, $\theta = 15^\circ$

We use trigonometry: $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{h}{d}$
So, $d = \frac{h}{\sin(\theta)}$

The work done by the force is $\boxed{\text{3863 J}}$.