This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to question 12: a) What is the work done on the trolley against the gravitational force in moving from A to B? Step 1: Identify the given values. Mass of trolley, m = 30 kg Vertical height gained, h = 10 m Acceleration due to gravity, g = 10 m/s^2 (assuming this standard approximation) Step 2: Use the formula for work done against gravity (change in gravitational potential energy). W_g = mgh Step 3: Substitute the values and calculate. W_g = (30 kg) × (10 m/s^2) × (10 m) W_g = 3000 J The work done against the gravitational force is 3000 J. b) Determine the work done by the force in moving the trolley from A to B. Step 1: Identify the given values. Applied force, F = 100 N (parallel to the slope) Vertical height, h = 10 m Angle of inclination, = 15^ Step 2: Calculate the distance moved along the slope (d). We use trigonometry: () = oppositehypotenuse = (h)/(d) So, d = (h)/(()) d = 10 m(15^) d ≈ 10 m0.2588 d ≈ 38.63 m Step 3: Use the formula for work done by a force acting parallel to the displacement. W_F = F × d Step 4: Substitute the values and calculate. W_F = (100 N) × (38.63 m) W_F ≈ 3863 J The work done by the force is 3863 J.