This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here's the solution for question 5: Part a) The stress. Step 1: Calculate the cross-sectional area of the rod. The diameter (D) is 12 mm, which is 12 × 10^-3 m. The area (A) of a circular cross-section is given by ((D)/(2))^2. Use = 3.142. A = ((D)/(2))^2 A = 3.142 × (12 × 10^-3 m2)^2 A = 3.142 × (6 × 10^-3 m)^2 A = 3.142 × (36 × 10^-6 m^2) A = 1.13112 × 10^-4 m^2 Step 2: Convert the force to Newtons. The force (F) is 30 kN, which is 30 × 10^3 N. Step 3: Calculate the stress in the rod. Stress () is force per unit area. = (F)/(A) = 30 × 10^3 N1.13112 × 10^-4 m^2 = 265221000.7 Pa = 265.22 × 10^6 Pa = 265.22 MPa Part b) The strain. Step 1: Identify the change in length and original length. The change in length ( L) is 0.3 m. The original length (L) is 2.4 m. Step 2: Calculate the strain. Strain () is the ratio of the change in length to the original length. = ( L)/(L) = 0.3 m2.4 m = 0.125 = 0.125 That's 2 down. 3 left today — send the next one.