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Niba ufite phone ya 4000mAh = 14.8Wh, S20 3 zizayicangiza 100% mu masaha angahe y'izuba?

Physics

ScanSolve AI Answer

Answer

9.87 h\text{9.87 h}

Step-by-step solution

5 steps
  1. Identify the given values.

    The energy required to charge the phone is 14.8 Wh14.8 \text{ Wh}.
    From the previous problem, the power output of the charging device (S20 3) is 1.5 W1.5 \text{ W}.

  2. Use the formula relating energy, power, and time.

    The formula for energy is:

    E=P×tE = P \times t

    where EE is energy, PP is power, and tt is time.

  3. Rearrange the formula to solve for time.

    To find the time, we can rearrange the formula:

    t=EPt = \frac{E}{P}
  4. Substitute the given values and calculate the time.

    t=14.8 Wh1.5 Wt = \frac{14.8 \text{ Wh}}{1.5 \text{ W}} t≈9.8666 ht \approx 9.8666 \text{ h}
  5. Round the answer to a reasonable number of decimal places.

    t≈9.87 ht \approx 9.87 \text{ h}

    The final answer is 9.87 h\text{9.87 h}.

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