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Physics
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Step-by-step solution
10 stepsIdentify the given information.
The problem provides the following values:
- Initial velocity (v₀) = 15 m/s
- Angle (θ) = 30°
- Acceleration due to gravity (g) = 9.8 m/s²
Determine what needs to be calculated.
The question asks for the maximum height reached by the projectile.
Recall the relevant physics formula.
The formula for the maximum height (H) of a projectile is:
H = (v₀² * sin²(θ)) / (2 * g)Substitute the given values into the formula.
H = (15 m/s)² * sin²(30°) / (2 * 9.8 m/s²)
Calculate the square of the initial velocity.
15² = 225 m²/s²
Calculate the sine of the angle and square it.
sin(30°) = 0.5
sin²(30°) = (0.5)² = 0.25Calculate the denominator.
2 * 9.8 m/s² = 19.6 m/s²
Substitute these calculated values back into the formula for H.
H = (225 m²/s² * 0.25) / (19.6 m/s²)
Calculate the numerator.
225 * 0.25 = 56.25 m²/s²
Perform the final division to find the maximum height.
H = 56.25 m²/s² / 19.6 m/s²
H ≈ 2.87 mThe maximum height reached by the projectile is approximately 2.87 meters.
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