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Physics

ScanSolve AI Answer

Step-by-step solution

10 steps
  1. Identify the given information.

    The problem provides the following values:

    • Initial velocity (v₀) = 15 m/s
    • Angle (θ) = 30°
    • Acceleration due to gravity (g) = 9.8 m/s²
  2. Determine what needs to be calculated.

    The question asks for the maximum height reached by the projectile.

  3. Recall the relevant physics formula.

    The formula for the maximum height (H) of a projectile is:
    H = (v₀² * sin²(θ)) / (2 * g)

  4. Substitute the given values into the formula.

    H = (15 m/s)² * sin²(30°) / (2 * 9.8 m/s²)

  5. Calculate the square of the initial velocity.

    15² = 225 m²/s²

  6. Calculate the sine of the angle and square it.

    sin(30°) = 0.5
    sin²(30°) = (0.5)² = 0.25

  7. Calculate the denominator.

    2 * 9.8 m/s² = 19.6 m/s²

  8. Substitute these calculated values back into the formula for H.

    H = (225 m²/s² * 0.25) / (19.6 m/s²)

  9. Calculate the numerator.

    225 * 0.25 = 56.25 m²/s²

  10. Perform the final division to find the maximum height.

    H = 56.25 m²/s² / 19.6 m/s²
    H ≈ 2.87 m

    The maximum height reached by the projectile is approximately 2.87 meters.

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