An object falls freely fr a height of 25m onto the roof of a building 5m high. Calculate the velocity with which the object strikes the roof (g=10ms-¹)

Physics

ScanSolve AI Answer

Answer

20 m s−120 \ \mathrm{m\,s^{-1}}

Step-by-step solution

4 steps
  1. Identify the quantities.

    The object falls from a height of 25 m25\,\mathrm{m} (above ground) onto the roof at 5 m5\,\mathrm{m} (above ground).
    Thus, distance fallen s=25−5=20 ms=25-5=20\,\mathrm{m}.
    Initial velocity u=0 m s−1u=0\,\mathrm{m\,s^{-1}} (freely falling from rest).
    Acceleration a=g=10 m s−2a=g=10\,\mathrm{m\,s^{-2}}.

  2. Use the kinematic equation.

    v2=u2+2asv^{2}=u^{2}+2as
  3. Substitute the values.

    v2=02+2×10 m s−2×20 mv^{2}=0^{2}+2\times10\,\mathrm{m\,s^{-2}}\times20\,\mathrm{m} v2=400 m2 s−2v^{2}=400\,\mathrm{m^{2}\,s^{-2}}
  4. Solve for vv.

    v=400 m s−1v=\sqrt{400}\,\mathrm{m\,s^{-1}} v=20 m s−1v=20\,\mathrm{m\,s^{-1}}

    20 \ m,s^{-1}

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