We read your photo as:

Which of the poles of the magnet, labelled (c) and (d) in Figure 1, are North and South poles? Briefly state the function of the parts of the AC motor listed above (coil, magnets, carbon brushes and split rings/commutator) next to their names.

Physics

ScanSolve AI Answer

Answers

2 parts
b(i)

4 A\text{4 A}

b(ii)
40:1

Step-by-step solution

4 steps

here are the solutions to the physics questions:

Part 15

Part a(i)

The induced current law that allows us to find its direction is *Fleming's Right-Hand Rule

Part a(ii)

To determine the direction of the induced current, we use Fleming's Right-Hand Rule

  • Thumb: Direction of motion (downwards).
  • Forefinger: Direction of the magnetic field (to the right).
  • Middle finger: Direction of the induced current (into the page). Assuming the wire segment AB is oriented such that A is the end closer to the viewer and B is the end further into the page, the induced current will flow from A to B.

Part b(i)

4 A\text{4 A}

Calculate the current that would be taken by the lamp when operating normally.

  1. Identify the given values for the lamp.

    The lamp has a power (PP) of 24 W24 \text{ W} and operates at a voltage (VV) of 6 V6 \text{ V}.

  2. Use the power formula to calculate the current.

    The formula relating power, voltage, and current is P=VIP = VI.
    Rearranging for current (II):

    I=PVI = \frac{P}{V} I=24 W6 VI = \frac{24 \text{ W}}{6 \text{ V}} I=4 AI = 4 \text{ A}

    The current taken by the lamp is 4 A\boxed{\text{4 A}}.

Part b(ii)40:1

Calculate the turns ratio of the transformer that would be used.

  1. Identify the given voltages for the transformer.

    The primary voltage (VpV_p) is 240 V240 \text{ V}.
    The secondary voltage (VsV_s) is 6 V6 \text{ V} (the lamp's operating voltage).

  2. Use the transformer turns ratio formula.

    For an ideal transformer, the ratio of primary to secondary turns (Np/NsN_p/N_s) is equal to the ratio of primary to secondary voltages (Vp/VsV_p/V_s):

    NpNs=VpVs\frac{N_p}{N_s} = \frac{V_p}{V_s} NpNs=240 V6 V\frac{N_p}{N_s} = \frac{240 \text{ V}}{6 \text{ V}} NpNs=40\frac{N_p}{N_s} = 40

    The turns ratio of the transformer is 40:1\boxed{40:1}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp