We read your photo as:
State one effect of pressure on the: (i) freezing point of a liquid; (ii) boiling point of a liquid.
ScanSolve AI Answer
Answers
2 partsStep-by-step solution
4 stepsHere are the solutions to the remaining parts of your question, Philip.
Part b(i)
The effect of pressure on the freezing point of a liquid
For most substances, increasing pressure raises the freezing point. However, for water, increasing pressure lowers the freezing point.
Part b(ii)
The effect of pressure on the boiling point of a liquid
Increasing pressure raises the boiling point of a liquid.
Part c(i)
Step 1: Calculate the mass of hot and cold water delivered in 4 minutes.
Mass of hot water () = Rate of hot water Time
Mass of cold water () = Rate of cold water Time
Apply the principle of calorimetry (heat lost = heat gained).
Assuming no heat loss to the surroundings, the heat lost by the hot water equals the heat gained by the cold water. Let be the final temperature. The specific heat capacity of water () is the same for both.
Substitute the values and solve for .
The final temperature of the mixture is .
Part c(ii)
I. Step 1: Determine the range of the faulty thermometer and the true Celsius scale.
True Celsius scale:
Lower Fixed Point () =
Upper Fixed Point () =
Range =
Faulty thermometer:
Lower Fixed Point () =
Upper Fixed Point () =
Range =
Use the conversion formula for thermometer scales.
The ratio of the temperature difference from the lower fixed point to the total range is constant for both scales:
Let be the true temperature when the faulty thermometer reads .
Solve for the true temperature .
The temperature at normal pressure when the faulty thermometer reads is .
Try one yourself
A new problem that tests the same skill.
Still stuck on this one?
Ask a follow-up, and the answer starts from this question.
More Physics Questions

Handwritten Step-by-Step Solution
Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.
Try on WhatsApp