**Part a) The components of the circuit of figure 5 are: Rpot = 3.3 k, C = 0.1 , diac ST2 (VBO = 32V). The supply voltage is 120V, 60Hz. C

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Asked on April 26, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-04-26T16:58:01.612Z

Here is the complete solution for the practical problem: Part a) The components of the circuit of figure 5 are: $R_{pot} = 3.3 \text{ k}\Omega$, $C = 0.1 \mu\text{F}$, diac ST2 ($V_{BO} = 32\text{V}$). The supply voltage is $120\text{V}$, $60\text{Hz}$. Calculate: i) The time of firing and the period of conduction of the triac when the potentiometer R, is varied to $130 \Omega$. Step 1: Calculate the peak supply voltage ($V_m$) and the total resistance ($R_{total}$). The RMS supply

Accepted Answer · 2026-04-26T16:58:01.612Z

Here is the complete solution for the practical problem: Part a) The components of the circuit of figure 5 are: $R_{pot} = 3.3 \text{ k}\Omega$, $C = 0.1 \mu\text{F}$, diac ST2 ($V_{BO} = 32\text{V}$). The supply voltage is $120\text{V}$, $60\text{Hz}$. Calculate: i) The time of firing and the period of conduction of the triac when the potentiometer R, is varied to $130 \Omega$. Step 1: Calculate the peak supply voltage ($V_m$) and the total resistance ($R_{total}$). The RMS supply

**Part a) The components of the circuit of figure 5 are: Rpot = 3.3 k, C = 0.1 , diac ST2 (VBO = 32V). The supply voltage is 120V, 60Hz. C

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**Part a) The components of the circuit of figure 5 are: Rpot = 3.3 k, C = 0.1 , diac ST2 (VBO = 32V). The supply voltage is 120V, 60Hz. C

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