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Calculate the potential energy of the horse while standing on the hill

Physics

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2 parts
13

1300 J\text{1300 J}

14

1250 J\text{1250 J}

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6 steps

Here are the solutions to the physics problems:

Part 13· 3 steps

Calculate the potential energy of the horse while standing on the hill.

  1. Identify the given values.

    Mass of horse, m=100 kgm = 100 \text{ kg}
    Height of hill, h=1.3 mh = 1.3 \text{ m}
    Acceleration due to gravity, g=10 m/s2g = 10 \text{ m/s}^2

  2. Use the formula for potential energy (PEPE).

    PE=mghPE = mgh

  3. Substitute the values and calculate.

    PE=(100 kg)×(10 m/s2)×(1.3 m)PE = (100 \text{ kg}) \times (10 \text{ m/s}^2) \times (1.3 \text{ m}) PE=1000×1.3 JPE = 1000 \times 1.3 \text{ J} PE=1300 JPE = 1300 \text{ J}

    The potential energy is 1300 J\boxed{\text{1300 J}}.

Part 14

1250 J\text{1250 J}

Calculate the kinetic energy used to run down the hill.

  1. Identify the given values.

    Mass of horse, m=100 kgm = 100 \text{ kg}
    Speed of horse, v=5.0 m/sv = 5.0 \text{ m/s}

  2. Use the formula for kinetic energy (KEKE).

    KE=12mv2KE = \frac{1}{2}mv^2

  3. Substitute the values and calculate.

    KE=12×(100 kg)×(5.0 m/s)2KE = \frac{1}{2} \times (100 \text{ kg}) \times (5.0 \text{ m/s})^2 KE=12×100 kg×25 m2/s2KE = \frac{1}{2} \times 100 \text{ kg} \times 25 \text{ m}^2/\text{s}^2 KE=50×25 JKE = 50 \times 25 \text{ J} KE=1250 JKE = 1250 \text{ J}

    The kinetic energy is 1250 J\boxed{\text{1250 J}}.

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