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Define temperature, distance, speed, and velocity. Calculate the average speed of a car that travels 150 km in 3 hours.

Physics

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2 parts
b(i)

50 km/h\text{50 km/h}

b(ii)

13.89 m/s\text{13.89 m/s}

Step-by-step solution

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Here are the answers to your questions:

1.c) iv) Temperature (5 marks)
Temperature is a physical quantity that expresses the degree of hotness or coldness of a substance. It is a measure of the average kinetic energy of the particles within a system. Its SI unit is the Kelvin (K\text{K}).

2.a) Define the following terms.

Part i

Distance (2 marks)

Distance is the total length of the path covered by an object during its motion, irrespective of the direction of travel. It is a scalar quantity.

Part ii

Speed (2 marks)

Speed is the rate at which an object covers distance. It is defined as the distance traveled per unit time and is a scalar quantity.

Part iii

Velocity (2 marks)

Velocity is the rate of change of displacement of an object. It is defined as the displacement per unit time and is a vector quantity, meaning it has both magnitude and direction.

Part b(i)

50 km/h\text{50 km/h}

Calculate its average speed. (4 marks)

A car travels a distance of 150 km in 3 hours.

  1. State the formula for average speed.

    Average Speed=Total DistanceTotal Time\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}
  2. Substitute the given values.

    Total Distance=150 km\text{Total Distance} = 150 \text{ km} Total Time=3 hours\text{Total Time} = 3 \text{ hours} Average Speed=150 km3 hours\text{Average Speed} = \frac{150 \text{ km}}{3 \text{ hours}}
  3. Calculate the average speed.

    Average Speed=50 km/h\text{Average Speed} = 50 \text{ km/h}

    The average speed of the car is 50 km/h\boxed{\text{50 km/h}}.

Part b(ii)

13.89 m/s\text{13.89 m/s}

Convert the speed into m/s. (4 marks)

  1. Convert kilometers to meters.

    1 km=1000 m1 \text{ km} = 1000 \text{ m} 150 km=150×1000 m=150000 m150 \text{ km} = 150 \times 1000 \text{ m} = 150000 \text{ m}
  2. Convert hours to seconds.

    1 hour=60 minutes1 \text{ hour} = 60 \text{ minutes} 1 minute=60 seconds1 \text{ minute} = 60 \text{ seconds} 1 hour=60×60 seconds=3600 seconds1 \text{ hour} = 60 \times 60 \text{ seconds} = 3600 \text{ seconds} 3 hours=3×3600 seconds=10800 seconds3 \text{ hours} = 3 \times 3600 \text{ seconds} = 10800 \text{ seconds}
  3. Calculate the speed in m/s using the converted values.

    Speed=Distance in metersTime in seconds=150000 m10800 s\text{Speed} = \frac{\text{Distance in meters}}{\text{Time in seconds}} = \frac{150000 \text{ m}}{10800 \text{ s}} Speed≈13.888... m/s\text{Speed} \approx 13.888... \text{ m/s}

    Rounding to two decimal places:

    Speed≈13.89 m/s\text{Speed} \approx 13.89 \text{ m/s}

    The speed of the car in m/s is 13.89 m/s\boxed{\text{13.89 m/s}}.

    Alternatively, convert the calculated speed directly:

    50 km/h=50×1000 m3600 s50 \text{ km/h} = 50 \times \frac{1000 \text{ m}}{3600 \text{ s}} 50 km/h=500003600 m/s50 \text{ km/h} = \frac{50000}{3600} \text{ m/s} 50 km/h≈13.89 m/s50 \text{ km/h} \approx 13.89 \text{ m/s}

Part c

State two differences between speed and velocity. (4 marks)

  1. Scalar vs. Vector: Speed is a scalar quantity, meaning it only has magnitude. Velocity is a vector quantity, meaning it has both magnitude and direction.
  2. Definition: Speed is the rate of change of distance, while velocity is the rate of change of displacement.

Part d

Sketch a distance-time graph for uniform motion. (2 marks)

For uniform motion, an object covers equal distances in equal intervals of time. Therefore, a distance-time graph for uniform motion is a straight line with a positive constant slope, starting from the origin (if motion starts from rest at zero distance).

3.a) What is force. (2 marks)
Force is an influence that can cause an object with mass to change its velocity (i.e., to accelerate). It is a vector quantity, having both magnitude and direction, and its SI unit is the Newton (N\text{N}).

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