This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Step 1: Calculate the cross-sectional area of the rod. The diameter of the rod is D = 80 mm. First, convert the diameter to meters: D = 80 × 10^-3 m = 0.08 m. The radius of the rod is r = D/2 = 0.08 m / 2 = 0.04 m. The cross-sectional area A of a circular rod is given by the formula A = r^2. A = (0.04 m)^2 = × 0.0016 m^2 ≈ 0.0050265 m^2 Step 2: Calculate the tensile stress. Tensile stress () is defined as the tensile force (F) divided by the cross-sectional area (A). The tensile force is given as F = 900 N. = (F)/(A) = 900 N0.0050265 m^2 ≈ 179047.6 Pa Step 3: Convert the stress to megapascals (MPa). Since 1 MPa = 10^6 Pa, we divide the stress in Pascals by 10^6. ≈ (179047.6)/(10^6) MPa ≈ 0.179 MPa The tensile stress is 0.179 MPa. 3 done, 2 left today. You're making progress.