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The calculations the mass of the metre rule using the formula above. (b) Using the data from the table in fig. 3.3, calculate d and d, when the position of the mass is 20 cm. (c) Using the values of d, and d, from (b) calculate the force of the metre rule.

Physics

ScanSolve AI Answer

Due to the poor image quality and missing "Fig. 3.1" table, the following assumptions are made for parts (a), (b), and (c):

  • The pivot position (PP) is 40 cm.
  • The mass of the object (MobjectM_{object}) is 100 g.
  • The definition of X2, "X2 = (200 - position of the pivot)", contains a typo. It is assumed that "200" should be "50" (representing the center of mass of a 100 cm metre rule), making X2=(50−position of the pivot)X2 = (50 - \text{position of the pivot}).
  • The formula in part (a) is "mass = X1 / (X2 + X3) * mass_of_object". It is assumed that X3 = 0, so the formula used is Mrule=Mobject×X1X2M_{rule} = M_{object} \times \frac{X1}{X2}.

a) The formula for the mass of the metre rule, based on the given information and assumptions, is:

Mrule=Mobject×X1X2M_{rule} = M_{object} \times \frac{X1}{X2}

Where:
X1=(position of the pivot−position of mass)X1 = (\text{position of the pivot} - \text{position of mass})
X2=(50−position of the pivot)X2 = (50 - \text{position of the pivot})

b) Step 1: Calculate X1.
Given: Position of the mass (LL) = 20 cm.
Assumed: Position of the pivot (PP) = 40 cm.

X1=P−LX1 = P - L X1=40 cm−20 cmX1 = 40 \text{ cm} - 20 \text{ cm} X1=20 cmX1 = 20 \text{ cm}

Step 2: Calculate X2.
Assumed: Position of the pivot (PP) = 40 cm.

X2=50 cm−PX2 = 50 \text{ cm} - P X2=50 cm−40 cmX2 = 50 \text{ cm} - 40 \text{ cm} X2=10 cmX2 = 10 \text{ cm}

b) X1=20 cmX1 = \boxed{20 \text{ cm}}, X2=10 cmX2 = \boxed{10 \text{ cm}}

c) Step 3: Calculate the mass of the metre rule.
Using the formula Mrule=Mobject×X1X2M_{rule} = M_{object} \times \frac{X1}{X2}.
Assumed: Mobject=100M_{object} = 100 g.
Calculated: X1=20X1 = 20 cm, X2=10X2 = 10 cm.

Mrule=100 g×20 cm10 cmM_{rule} = 100 \text{ g} \times \frac{20 \text{ cm}}{10 \text{ cm}} Mrule=100 g×2M_{rule} = 100 \text{ g} \times 2 Mrule=200 gM_{rule} = 200 \text{ g}

c) The mass of the metre rule is 200 g\boxed{200 \text{ g}}.

d) Step 4: Explain the importance of using all values.
Using multiple readings (all values) and calculating an average helps to minimize the impact of random errors and inaccuracies in individual measurements. This leads to a more reliable and accurate determination of the metre rule's mass.

e) Step 5: Describe how to find the mass of a small stone.

  1. Balance the metre rule at its center of mass (50 cm mark) on a pivot.
  2. Place the small stone at a known position on one side of the pivot.
  3. Place a known standard mass on the other side of the pivot and adjust its position until the rule balances horizontally.
  4. Measure the distance of the stone from the pivot (dstoned_{stone}) and the distance of the known mass from the pivot (dknownd_{known}).
  5. Apply the principle of moments: Mstone×dstone=Mknown×dknownM_{stone} \times d_{stone} = M_{known} \times d_{known}.
  6. Calculate the mass of the stone (MstoneM_{stone}).
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