We read your photo as:

What are the dimensions of Work and Power?

Physics

ScanSolve AI Answer

Step-by-step solution

2 steps
  1. Determine the dimensions of Work.

    Work (WW) is defined as force (FF) multiplied by distance (dd).

    W=F⋅dW = F \cdot d

    Force is defined as mass (mm) multiplied by acceleration (aa).

    F=m⋅aF = m \cdot a

    The fundamental dimensions are Mass (MM), Length (LL), and Time (TT).
    The dimensions of mass are [M][M].
    The dimensions of distance are [L][L].
    The dimensions of acceleration are [L][T]−2[L][T]^{-2} (since acceleration is change in velocity over time, and velocity is change in distance over time).

    Substitute the dimensions for force:

    [F]=[M]⋅[L][T]−2=[M][L][T]−2[F] = [M] \cdot [L][T]^{-2} = [M][L][T]^{-2}

    Now, substitute the dimensions for work:

    [W]=[F]⋅[d]=([M][L][T]−2)⋅[L]=[M][L]2[T]−2[W] = [F] \cdot [d] = ([M][L][T]^{-2}) \cdot [L] = [M][L]^2[T]^{-2}

    The dimensions of Work are [M][L]2[T]−2\boxed{[M][L]^2[T]^{-2}}.

  2. Determine the dimensions of Power.

    Power (PP) is defined as work (WW) done per unit time (tt).

    P=WtP = \frac{W}{t}

    From Step 1, the dimensions of Work are [M][L]2[T]−2[M][L]^2[T]^{-2}.
    The dimensions of time are [T][T].

    Substitute the dimensions for power:

    [P]=[M][L]2[T]−2[T]=[M][L]2[T]−2[T]−1=[M][L]2[T]−3[P] = \frac{[M][L]^2[T]^{-2}}{[T]} = [M][L]^2[T]^{-2}[T]^{-1} = [M][L]^2[T]^{-3}

    The dimensions of Power are [M][L]2[T]−3\boxed{[M][L]^2[T]^{-3}}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp