The displacement equation of wave is y=0.02 sin(5x-100t).what is it's frequency

Step 1: Identify the angular frequency from the wave equation. The general displacement equation for a sinusoidal wave is given by $y = A \sin(kx - \omega t)$, where $\omega$ is the angular frequency. Comparing the given equation $y = 0.02 \sin(5x - 100t)$ with the general form, we can identify the angular frequency: $\omega = 100 \text{ rad/s}$

Step 2: Calculate the frequency using the angular frequency. The relationship between angular frequency $\omega$ and frequency $f$ is: $\omega = 2\pi f$ Rearranging to solve for $f$: $f = \frac{\omega}{2\pi}$ Substitute the value of $\omega$: $f = \frac{100 rad/s}{2\pi}$ $f = \frac{50}{\pi} \text{ Hz}$ Using $\pi \approx 3.14159$: $f \approx \frac{50}{3.14159} \text{ Hz}$ $f \approx 15.92 \text{ Hz}$

The frequency of the wave is $\boxed{15.92 Hz}$.

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