The displacement equation of wave is y=0.02 sin(5x-100t).what is it's frequency

The general displacement equation for a sinusoidal wave is given by $y = A \sin(kx - \omega t)$, where $\omega$ is the angular frequency.
Comparing the given equation $y = 0.02 \sin(5x - 100t)$ with the general form, we can identify the angular frequency:

$$\omega = 100 \text{ rad/s}$$

The relationship between angular frequency $\omega$ and frequency $f$ is:

$$\omega = 2\pi f$$

Rearranging to solve for $f$:

$$f = \frac{\omega}{2\pi}$$

Substitute the value of $\omega$:

$$f = \frac{100 \text{ rad/s}}{2\pi}$$ $$f = \frac{50}{\pi} \text{ Hz}$$

Using $\pi \approx 3.14159$:

$$f \approx \frac{50}{3.14159} \text{ Hz}$$ $$f \approx 15.92 \text{ Hz}$$

The frequency of the wave is $\text{15.92 Hz}$.