This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey, good to see you again. Here's the solution to your physics question: Physics Question 11: The gravitational pull between two bodies is 20N. Find the gravitational pull when their distance of separation is doubled. Step 1: Recall Newton's Law of Universal Gravitation. The gravitational force (F) between two bodies is inversely proportional to the square of the distance (r) between their centers. F (1)/(r^2) This can be written as: F = G (m_1 m_2)/(r^2) where G is the gravitational constant, and m_1 and m_2 are the masses of the two bodies. Step 2: Set up the initial condition. Let the initial gravitational pull be F_1 = 20 N at an initial distance r_1. So, F_1 = G (m_1 m_2)/(r_1^2) = 20 N Step 3: Calculate the new gravitational pull when the distance is doubled. The new distance of separation is r_2 = 2r_1. Let the new gravitational pull be F_2. F_2 = G (m_1 m_2)/(r_2^2) Substitute r_2 = 2r_1 into the equation: F_2 = G (m_1 m_2)/((2r_1)^2) F_2 = G (m_1 m_2)/(4r_1^2) F_2 = (1)/(4) ( G (m_1 m_2)/(r_1^2) ) From Step 2, we know that G (m_1 m_2)/(r_1^2) = F_1. So, F_2 = (1)/(4) F_1 F_2 = (1)/(4) (20 N) F_2 = 5 N The final answer is D) 5N. Send me the next one 📸