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What is the heat radiated per second by a person given their body temperature, environment temperature, surface area, and emissivity?

Physics

ScanSolve AI Answer

To find the heat radiated per second by the person, we use the Stefan-Boltzmann Law for thermal radiation. The question asks for the heat the person radiates, which implies the gross emission from the person's body, not the net heat exchange with the environment.

Given values:

  • Normal body temperature (TbodyT_{body}) = 37∘C37^\circ\text{C}
  • Environment temperature (TenvT_{env}) = 67∘C67^\circ\text{C}
  • Body surface area (AA) = 2 m22 \text{ m}^2
  • Stefan-Boltzmann constant (σ\sigma) = 5.67×10−8 Wm−2K−45.67 \times 10^{-8} \text{ Wm}^{-2}\text{K}^{-4}
  • Emissivity ($\epsilon
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