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What is the maximum relative centrifugal force applied when red blood cells are sedimented at 1000 rpm in a rotor of maximum sample radius equal to 10 cm?

Physics

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  • What is the maximum relative centrifugal force applied when red blood cells are sedimented at 1000 rpm in a rotor of maximum sample radius equal to 10 cm?
  1. Identify the given values.

    The formula for RCF (G-force) is:

    RCF=1.12×r×(RPM1000)2RCF = 1.12 \times r \times \left(\frac{RPM}{1000}\right)^2

    Given:
    r=10 cmr = 10 \text{ cm}
    RPM=1000 rpmRPM = 1000 \text{ rpm}

  2. Substitute the values into the formula.

    RCF=1.12×10 cm×(1000 rpm1000)2RCF = 1.12 \times 10 \text{ cm} \times \left(\frac{1000 \text{ rpm}}{1000}\right)^2
  3. Calculate the RCF.

    RCF=1.12×10×(1)2RCF = 1.12 \times 10 \times (1)^2 RCF=1.12×10×1RCF = 1.12 \times 10 \times 1 RCF=11.2RCF = 11.2

    The maximum relative centrifugal force is 11.2 G\boxed{\text{11.2 G}}.

    • Calculate the G force applied in sedimenting starch suspension at 50 rpm in a rotor of sample radius 200 mm.
  4. Identify the given values and convert units if necessary.

    The formula for RCF (G-force) is:

    RCF=1.12×r×(RPM1000)2RCF = 1.12 \times r \times \left(\frac{RPM}{1000}\right)^2

    Given:
    r=200 mmr = 200 \text{ mm}
    RPM=50 rpmRPM = 50 \text{ rpm}

    Convert the radius from millimeters to centimeters:

    r=200 mm=200×110 cm=20 cmr = 200 \text{ mm} = 200 \times \frac{1}{10} \text{ cm} = 20 \text{ cm}
  5. Substitute the values into the formula.

    RCF=1.12×20 cm×(50 rpm1000)2RCF = 1.12 \times 20 \text{ cm} \times \left(\frac{50 \text{ rpm}}{1000}\right)^2
  6. Calculate the RCF.

    RCF=1.12×20×(0.05)2RCF = 1.12 \times 20 \times (0.05)^2 RCF=1.12×20×0.0025RCF = 1.12 \times 20 \times 0.0025 RCF=22.4×0.0025RCF = 22.4 \times 0.0025 RCF=0.056RCF = 0.056

    The G force applied is 0.056 G\boxed{\text{0.056 G}}.

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