The problem describes a technician sliding from a tower of height 80 m. We are given the acceleration due to…

Question

The problem describes a technician sliding from a tower of height 80 m. We are given the acceleration due to gravity g = 10 N/Kg. We will assume the technician starts from rest and

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The problem describes a technician sliding from a tower of height $80 \text{ m}$ . We are given the acceleration due to gravity $g = 10 \text{ N/Kg}$ . We will assume the technician starts from rest and the question asks for the speed just before hitting the ground.

Given:

Initial velocity, $u = 0 \text{ m/s}$ (assuming the technician starts from rest)
Height, $h = 80 \text{ m}$
Acceleration due to gravity, $g = 10 \text{ N/Kg} = 10 \text{ m/s}^2$

We need to find the final velocity, $v$ .

Identify the appropriate kinematic equation.
To find the final velocity when initial velocity, acceleration, and displacement are known, we use the following equation:
$v^2 = u^2 + 2gh$
Substitute the given values into the equation.
$v^2 = (0 \text{ m/s})^2 + 2(10 \text{ m/s}^2)(80 \text{ m})$
Calculate the square of the final velocity.
$v^2 = 0 + 1600 \text{ m}^2/\text{s}^2$ $v^2 = 1600 \text{ m}^2/\text{s}^2$
Calculate the final velocity by taking the square root.
$v = \sqrt{1600 \text{ m}^2/\text{s}^2}$ $v = 40 \text{ m/s}$
The speed of the technician just before hitting the ground is $\boxed{\text{40 m/s}}$ .

The problem describes a technician sliding from a tower of height 80 m. We are given the acceleration due to gravity g = 10 N/Kg. We will assume the technician starts from rest and

Answer

Step-by-step solution

Identify the appropriate kinematic equation.

Substitute the given values into the equation.

Calculate the square of the final velocity.

Calculate the final velocity by taking the square root.

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