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The problem states that for every 2 psi drop in pressure, the temperature rises by 3 degrees. This indicates a linear relationship between temperature and pressure, T = mP + c.

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Question 3

1. Derive the formula which shows the interrelationship between pressure and temperature.

Let PP be the pressure in psi and TT be the temperature in degrees.
The problem states that for every 2 psi drop in pressure, the temperature rises by 3 degrees. This indicates a linear relationship between temperature and pressure, T=mP+cT = mP + c.

Step 1: Determine the slope (mm).
The change in pressure is ΔP=−2\Delta P = -2 psi (pressure drops).
The change in temperature is ΔT=+3\Delta T = +3 degrees (temperature rises).
The slope mm is given by:

m=ΔTΔP=3−2=−32m = \frac{\Delta T}{\Delta P} = \frac{3}{-2} = -\frac{3}{2}

Step 2: Use the given point to find the y-intercept (cc).
We are given that when the pressure is P=2P = 2 psi, the temperature is T=−12T = -12 degrees.
Substitute these values and the slope into the linear equation T=mP+cT = mP + c:

−12=(−32)(2)+c-12 = \left(-\frac{3}{2}\right)(2) + c −12=−3+c-12 = -3 + c

Step 3: Solve for cc.

c=−12+3c = -12 + 3 c=−9c = -9

Step 4: Write the final formula.
Substitute the slope m=−32m = -\frac{3}{2} and the y-intercept c=−9c = -9 into T=mP+cT = mP + c:

T=−32P−9T = -\frac{3}{2}P - 9

The formula showing the interrelationship between pressure and temperature is:

T=−32P−9\boxed{T = -\frac{3}{2}P - 9}

2. Draw the graph of the above function, show the intersection points on the graph with the axes precisely.

The function is T=−32P−9T = -\frac{3}{2}P - 9.
To draw the graph, we find the intercepts with the axes.

Step 1: Find the T-intercept (where P=0P=0).
Substitute P=0P=0 into the equation:

T=−32(0)−9T = -\frac{3}{2}(0) - 9 T=−9T = -9

The T-intercept is (0,−9)(0, -9).

Step 2: Find the P-intercept (where T=0T=0).
Substitute T=0T=0 into the equation:

0=−32P−90 = -\frac{3}{2}P - 9

Add 9 to both sides:

9=−32P9 = -\frac{3}{2}P

Multiply by −23-\frac{2}{3} to solve for PP:

P=9×(−23)P = 9 \times \left(-\frac{2}{3}\right) P=−3×2P = -3 \times 2 P=−6P = -6

The P-intercept is (−6,0)(-6, 0).

Step 3: Draw the graph.
Plot the two intercepts (0,−9)(0, -9) and (−6,0)(-6, 0) and draw a straight line through them.
The horizontal axis represents Pressure (PP in psi) and the vertical axis represents Temperature (TT in degrees).

      ^ T (degrees)
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