The problem states that the water does not rebound, meaning its final velocity after impact is 0 ms⁻¹.

The speed of the water stream is $v = 15 \text{ ms}^{-1}$.
The cross-sectional area of the tube is $A = 10^{-2} \text{ m}^2$.
The density of water is $\rho = 1000 \text{ kg m}^{-3}$.
The problem states that the water does not rebound, meaning its final velocity after impact is $0 \text{ ms}^{-1}$.

The force exerted by a fluid stream on a surface is equal to the rate of change of momentum of the fluid. Since the water does not rebound, its final momentum is zero.
The mass of water hitting the wall per unit time (mass flow rate) is given by $\frac{dm}{dt} = \rho A v$.
The initial momentum per unit time is $\frac{d(mv)}{dt} = v \frac{dm}{dt}$.
Since the final velocity is zero, the change in momentum per unit time (which is the force) is:

Substitute the expression for mass flow rate:

The calculated force is $2250 \text{ N}$, which matches option (4).