The question states: "A motorcycle starting from rest accelerates uniformly to a velocity of 24 km/h in 10 seconds.

Here's the solution to the problem from the image. The question states: "A motorcycle starting from rest accelerates uniformly to a velocity of 24 km/h in 10 seconds. a) What is its acceleration? b) How far does it travel during this time?" First, convert the final velocity from km/h to m/s. 24 km/h = 24 × 1000 m3600 s = (24000)/(3600) m/s = (240)/(36) m/s = (20)/(3) m/s ≈ 6.67 m/s Given: Initial velocity, u = 0 m/s (starting from rest) Final velocity, v = (20)/(3) m/s Time, t = 10 s a) What is its acceleration? Step 1: Use the kinematic equation relating initial velocity, final velocity, acceleration, and time. The formula is v = u + at. Step 2: Substitute the given values into the formula. (20)/(3) m/s = 0 m/s + a × 10 s Step 3: Solve for acceleration (a). a = (20)/(3) m/s10 s a = (20)/(3 × 10) m/s^2 a = (20)/(30) m/s^2 a = (2)/(3) m/s^2 The acceleration is 0.67 m/s^2. b) How far does it travel during this time? Step 1: Use the kinematic equation for displacement. The formula is s = ut + (1)/(2)at^2. Step 2: Substitute the known values, including the acceleration found in part (a). s = (0 m/s)(10 s) + (1)/(2)((2)/(3) m/s^2)(10 s)^2 Step 3: Calculate the displacement (s). s = 0 + (1)/(2) × (2)/(3) m/s^2 × 100 s^2 s = (1)/(3) × 100 m s = (100)/(3) m s ≈ 33.33 m The distance traveled is 33.33 m. 3 done, 2 left today. You're making progress.