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The question states: "A motorcycle starting from rest accelerates uniformly to a velocity of 24 km/h in 10 seconds.

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The question states: "A motorcycle starting from rest accelerates uniformly to a velocity of 24 km/h24 \text{ km/h} in 10 seconds10 \text{ seconds}.

a) What is its acceleration?

b) How far does it travel during this time?"

First, convert the final velocity from km/h\text{km/h} to m/s\text{m/s}.

24 km/h=24×1000 m3600 s=240003600 m/s=24036 m/s=203 m/s≈6.67 m/s24 \text{ km/h} = 24 \times \frac{1000 \text{ m}}{3600 \text{ s}} = \frac{24000}{3600} \text{ m/s} = \frac{240}{36} \text{ m/s} = \frac{20}{3} \text{ m/s} \approx 6.67 \text{ m/s}

Given:
Initial velocity, u=0 m/su = 0 \text{ m/s} (starting from rest)
Final velocity, v=203 m/sv = \frac{20}{3} \text{ m/s}
Time, t=10 st = 10 \text{ s}

a) What is its acceleration?

  1. Use the kinematic equation relating initial velocity, final velocity, acceleration, and time.

    The formula is v=u+atv = u + at.

  2. Substitute the given values into the formula.

    203 m/s=0 m/s+a×10 s\frac{20}{3} \text{ m/s} = 0 \text{ m/s} + a \times 10 \text{ s}
  3. Solve for acceleration (aa).

    a=203 m/s10 sa = \frac{\frac{20}{3} \text{ m/s}}{10 \text{ s}} a=203×10 m/s2a = \frac{20}{3 \times 10} \text{ m/s}^2 a=2030 m/s2a = \frac{20}{30} \text{ m/s}^2 a=23 m/s2a = \frac{2}{3} \text{ m/s}^2

    The acceleration is 0.67 m/s2\boxed{\text{0.67 m/s}^2}.

    b) How far does it travel during this time?

  4. Use the kinematic equation for displacement.

    The formula is s=ut+12at2s = ut + \frac{1}{2}at^2.

  5. Substitute the known values, including the acceleration found in part (a).

    s=(0 m/s)(10 s)+12(23 m/s2)(10 s)2s = (0 \text{ m/s})(10 \text{ s}) + \frac{1}{2}\left(\frac{2}{3} \text{ m/s}^2\right)(10 \text{ s})^2
  6. Calculate the displacement (ss).

    s=0+12×23 m/s2×100 s2s = 0 + \frac{1}{2} \times \frac{2}{3} \text{ m/s}^2 \times 100 \text{ s}^2 s=13×100 ms = \frac{1}{3} \times 100 \text{ m} s=1003 ms = \frac{100}{3} \text{ m} s≈33.33 ms \approx 33.33 \text{ m}

    The distance traveled is 33.33 m\boxed{\text{33.33 m}}.

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