Solve this fully

Comparing the given equation to the general form $y = A \sin \frac{2\pi}{\lambda} (vt - x)$, we can directly identify the amplitude.

$$A = 0.05 \text{ m}$$

Comparing the given equation to the general form, we can directly identify the wavelength.

$$\lambda = 0.8 \text{ m}$$

Comparing the term $(vt - x)$ in the general form with $(12t - x)$ in the given equation, we find the wave speed.

$$v = 12 \text{ m/s}$$

The relationship between wave speed ($v$), frequency ($f$), and wavelength ($\lambda$) is $v = f\lambda$.
Rearranging for frequency:

$$f = \frac{v}{\lambda}$$

Substitute the values for $v$ and $\lambda$:

$$f = \frac{12 \text{ m/s}}{0.8 \text{ m}}$$ $$f = 15 \text{ Hz}$$

The amplitude, wavelength, and frequency are:

• Amplitude ($A$): $\boxed{\text{0.05 m}}$
• Wavelength ($\lambda$): $\boxed{\text{0.8 m}}$
• Frequency ($f$): $\boxed{\text{15 Hz}}$